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sudokuEd
Grandmaster
Joined: 19 Jun 2006
Posts: 257
Location: Sydney Australia
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 Posted: Wed Jan 24, 2007 9:48 am Post subject: |
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Good work guys. Especially love step 28 - naked triple on those D's again. Nice find Richard.
I admire both of you for your tenacity. Thanks. 
Here's some moves - then a marks pic. There have been a few typos, so hope we are all at the same spot.
36. r9c6 = 7
36a. r1c3 = 1 -> r1c1 = 7, r9c3 = 4 ->r3c3 = 3 -> r7c7 = 8 -> r3c7 = 5 -> r9c7 = 3 ->r9c6 = 7
36b. r7c3 = 1 -> r1c3 = 4 -> r9c3 = 3 -> r9c6 = 7
36c. both 1's in c3 -> r9c6 = 7
37. r4c56 = [73]
38. r2c9 = 3
39. 7 on D/ in n3 -> no7 r1c8
40. no 9 in r9c1
40a. 9 in r2c2 -> 9 in n4 in c1 -> no 9 r9c1
40b. 9 in r2c8 -> no 9 r9c1
| Code: | .------------------------.------------------------.------------------------.
| 17 468 14 | 3 5 9 | 2 468 678 |
| 5 79 2 | 6 8 4 | 1 79 3 |
| 468 3468 39 | 7 2 1 | 58 45689 4689 |
:------------------------+------------------------+------------------------:
| 249 249 8 | 5 7 3 | 6 149 149 |
| 3 1 6 | 9 4 8 | 7 2 5 |
| 79 479 5 | 2 1 6 | 348 3489 489 |
:------------------------+------------------------+------------------------:
| 24689 2345689 19 | 148 369 25 | 38 34567 467 |
| 246 568 7 | 148 36 25 | 9 138 146 |
| 168 345689 34 | 148 69 7 | 345 1456 2 |
'------------------------'------------------------'------------------------'
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rcbroughton
Expert
Joined: 15 Nov 2006
Posts: 143
Location: London
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| Posted: Wed Jan 24, 2007 10:09 am Post subject: |
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| Para wrote: | still got the problem  |
I need a new k3yboard
Anyway- 3 more eliminations:
41. Conjugate pairs mean 9 in r2c8 or r6c1 -> no 9 in r6c8
41a. r2c8{97}->r2c2{79}->r3c3{39}->r9c3{34}->r1c3{14}->r1c1{17}->r6c1{79}
42. 3 cannot be in r7c8
42a. 3 either in r6c7 or r6c8. if r6c8 cannot be in r7c8
42a. if in r6c7 -> r6c7<>4 => r9c7=4 -> r9c3<>4 => r1c3=4 -> r1c3<>1 => r1c1=1 -> r1c1<>7 => r1c9=7 -> r2c8<>7 => r7c8=7
43. 3 can't be in r9c2
43a. 3 either in r3c2 or r3c3 if r3c2 -> not in r9c2
43b. if in r3c3 -> not in D\ in n9 -> r9c7=3 -> not in r9c2 |
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Para
Yokozuna
Joined: 08 Nov 2006
Posts: 384
Location: The Netherlands
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| Posted: Wed Jan 24, 2007 3:42 pm Post subject: |
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Step 43 is nice i love those diagonal empty rectangles.
44. R3C7 is not 8
44a. R3C7=8 -->> R7C7 =3 -->> R8C8 = 8 -->> R1C1 = 1 -->> R1C3=4; R9C1 = 6 -->> no options left for R3C1
45. naked single 5 in R3C7
46. Hidden single 5 in R8C6
47. Naked Single 2 in R7C6
48. Hidden single 2 in R8C1
49. Hidden single 2 in R4C2
50. ALS [R146C1] [R1C3] with common digit 1 eliminates other common digit 4 from R3C1. (it is also an APE, just think ALS sounds nicer  )
this is it so far. Dinner time.
[edit]
can't realy leave this out.
51. naked pair {34} in R9
52. xyz-wing in R8C2, R9C14 eliminates 8 from R9C2
Para |
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rcbroughton
Expert
Joined: 15 Nov 2006
Posts: 143
Location: London
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| Posted: Wed Jan 24, 2007 5:23 pm Post subject: |
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Para
Great moves - That solves it then. The key was the 5 in r3c7
53. ALS [r1c1 r2c2 r3c3 r7c7] =1=[r9c1 r8c2] -> no 8 in r7c2
54. 8 now locked in D/ of N7
55. ALS [r1c1 r1c9]=1=[r8c2 r8c5 r8c8] -> no 6 in r8c9
56. Hidden triple {567} in r7c8 r7c9 r9c8 for n9
57. 1 locked in row 8 of N9
58. naked pair {67} at r17c9 in row 9
59. hidden pair {18} r9c14
60. no 1 at r8c8
60a 1 at r1c1 -> no 1 at r8c8
60b. no 1 at r1c1 -> r8c9=1
and the rest is singles. |
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Para
Yokozuna
Joined: 08 Nov 2006
Posts: 384
Location: The Netherlands
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| Posted: Wed Jan 24, 2007 7:36 pm Post subject: |
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Nice job on finishing it
| rcbroughton wrote: |
55. ALS [r1c1 r1c9]=1=[r8c2 r8c5 r8c8] -> no 6 in r8c9
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Just wanted to point out this ALS also eliminates the 6 in R9C1. It doesn't matter much here but it might prove important some other day and it would be a shame to miss it
Para |
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