. This one was definitely harder than A74 Brick Wall since even finding those hypotheticals was difficult especially those moves between step 9 and 14 took me a long time to find.Now every Killer below 2.0 should help me to relax
.Since I try to shorten up my walkthroughs there might be some obvious moves I left out (e.g. step 4: R4C6 <> 7 because of R8C7)
on purpose because they're not needed to solve this assassin.
A60 RP Walkthrough:
1. R6789
a) Innies R89 = 4(2) = {13} locked for R8
b) 27(4) = 9{378/468/567} -> 9 locked between R9+N8 -> R9C45 <> 9
c) 14(3): R7C78 <> 1,3 because R8C7 = (13)
d) Innies N9 = 13(2) <> 1,2,3
e) Innies+Outies: 4 = R5C8 - R6C5
-> R5C8 = (56789), R6C5 = (12345)
2. C6789
a) Innies C89 = 7(2) <> 7,8,9; R2C8 <> 4,6
b) Innies+Outies: 4 = R8C5 - R5C6
-> R8C5 <> 4, R5C6 = (12345)
c) 13(3) @ N5 must have 6,7,8 xor 9 and it's only possible @ R5C5 -> R5C5 = (6789)
d) 14(3): R7C7 <> 2,4 because R7C8+R8C7 <= 9
e) Outies = 17(3): R6C5 <> 5 because Outies would be >= 18
3. C123
a) 22(3) = 9{58/67} -> 9 locked for N1
b) Innies = 17(4) -> R34C3 @ 17(3) <= 14 -> R3C4 <> 1,2
4. N5689
a) Outies = 8(1+1) <> 8,9; R3C8 <> 5,7
5. R6789+C6789
a) Outies R6789 = 17(3): R5C6 <> 5 because Outies would be >= 18
b) Innies+Outies R6789: 4 = R5C8 - R6C5 -> R5C8 <> 9
c) Innies+Outies C6789: 4 = R8C5 - R5C6 -> R8C5 <> 9
d) Killer pair (13) locked in 18(4) + 16(4) for R9
e) 27(4) = 69{48/57} -> 6 locked between R9+N8 -> R9C45 <> 6
6. N23
a) Innies+Outies: -8 = R1C3 - R3C48
-> R1C3 <> 8 because R3C48 <= 15
7. C123
a) Innies+Outies: R18C3 = R3C4 -> R3C4 <> 4 because R8C3 <> 1,3
b) 14(4): R6C1 <> 7 because 7{124} blocked by Killer pair (24) of 25(4)
c) 14(4): R6C1 <> 5 since 5{234} blocked by Killer pair (24) of 25(4) and
5{126} forces 25(4) = {4579} -> no candidate for R8C3
8. R789
a) 14(4) <> 7 because if 14(4) = {1247}:
- 25(4) = {2689} locked for N9 -> 14(4) = 2{47}1 -> R8C3 = 5; 1 locked in 18(4) for R9
- 16(4) = {2356} -> R8C4 = 6; 6 locked in 25(4) for R9 -> no 6 in 27(4) (step 5e)
b) Innies N7 = 20(5) = 13{259/268/457}: R78C3 <> 4 because
- R78C3 = {47} (because 7 only possible there) -> R7C12+R8C2 = {135} -> no combo for 14(4)
c) R3C8 <> 4 (step 4b)
d) 18(4) must have 1 xor 3 -> 18(4) <> 13{59/68}, <> {2457} and
<> {3456} because it's blocked by Killer triple (456) of Innies N9 = 13(2)
9. C123
a) Innies+Outies N7: -6 = R6C1 - R78C3: R7C3 <> 1 because
- only combos with 1 are R78C3 = 1[6/7] (since R78C3 >= 7)
- i) R78C3 = [16] -> Innies C123 = 17(4) = {2456} -> R34C3 @ 17(3) must be {45}
- R13C3 = 2[4/5] -> <> [25] since it's a Killer pair of 9(3) @ N1
- R13C3 = [24] -> Innies N1 = 14(3) = [284] -> no combo for 17(3) since it must be [485]
- ii) R78C3 = [17] -> Innies C123 = 17(4) = {2357} -> R34C3 @ 17(3) must be {45}
- R13C3 = 2[3/5] -> <> [25] (Killer pair of 9(3))
- R13C3 = [23] -> Innies N1 = 14(3) = [293] -> no combo for 17(3) since it must be [395]
b) 1 locked in 14(4) for N9 -> R6C1 <> 1; 14(4) = 1{238/256/346}
c) 14(4) <> 5 because:
- R7C12 = {25} (since (56) is a Killer pair of 25(4)) and R8C2 = 1
- Innies N7 = 20(5) must be {12359} -> not possible because R8C3 <> 3,9
-> 14(4) = 13{28/46}
d) Innies+Outies N7: -6 = R6C1 - R78C3: R7C3 <> 2 because
- only possible combos are R78C3 = 2[6/7]
- [27] impossible since it's a Killer pair of 25(4)
- R78C3 = [26] -> Innies C123 = {1367} -> because of Innies N1 = 14(3) and 17(3)
R134C3 must be [371]
- Innies N1 = 14(3) = [347]
- 20(3) = 4{79}, {79} locked for C1+N4
- {58} locked in 25(4) -> no combo for 25(4)
10. R789 !
a) 16(4) must have 1 xor 3 (step 5d, 8d) -> 16(4) <> 13{48/57}
b) 16(4) <> {1456} since it would force 25(4) = {2689} (2 only possible @ 25(4) + 18(4) for R89)
- 6 locked in 18(4) + 25(4) for R89 -> no 6 in 27(4) (step 5e)
c) ! 14(3) @ N9 <> 2 because
- 14(3) @ N9 = [923] -> Innies N7 = {13457}, R2C8 = 5 (step 2a) -> 14(4) = 6{34}1
- 6 locked in 25(4) = {2689} + 27(4) for R89
- 18(4) = {1458} -> 3 locked in 16(4) @ R9 = {2347} -> R8C3 = 7 -> R3C8 = 1 (step 4b)
- {48} locked for C8 and R9C9 = 1
- 23(4) @ N6 must have {67} -> impossible because 23(4) <> 1 and R6C8 <> 2,8
e) R2C8 <> 5 (Innies C89 = 7(2))
f) ! 2 locked in 18(4) + 16(4) for R89
g) 25(4) = 47{59/68} -> 4,7 locked for N7
h) R3C8 <> 1 (Outies N5689 = 8(1+1))
i) 14(4): R6C1 <> 6 because R7C12+R8C2 <> 4
j) Innies N7 = 20(5): R7C3 <> 5 because 9 only possible there
11. R123
a) Innies = 22(4): R3C13 <> 6 because
- possible combos are 6{259/349/358} since R3C8 = (23)
- {2569} -> R3C13 = {56} blocked by Killer pair (56) of 22(3)
- {3469} -> R3C13 = {46} -> Innies N1 = 14(3) = 46{?}
- {3568} -> R3C13 = {56} blocked by Killer pair (56) of 22(3) and
- R3C13 = {68} leaves no combo for Innies N1 = 14(3)
b) Innies N1 = 14(3): R3C1 <> 3 because
- I N1 = {356} blocked by Killer pair of (56) of 22(3)
- I N1 = [437] -> I R123 = 22(4) = 37{48} not possible because R3C8 <> 4,8
- I N1 = [734] -> I R123 = [3496] (not 34{78} because R3C8 <> 7,8) -> 17(3) = 49[?]
c) Innies N1 = 14(3) <> 6
- {356} blocked by Killer pair (56) of 22(3) -> I N1 = [671]
- I R123 = 71{59/68} -> 71{59} impossible because R3C8 <> 5,9
- I R123 = [7186] -> 17(3) = 18[?]
d) Innies N1 = 14(3) = {158/248/347} because {257} blocked by Killer pair (57) of 22(3)
e) 20(3) <> 3 because
- 20(3) = {389} -> R3C1 = 8 and 3 locked in 14(4) for C2 -> 9(3) = {126}
- no combo for 22(3)
12. C123
a) Consider combos of 20(3) -> R89C1 <> 5
- i) 20(3) = {479} -> R89C1 = (568) -> 25(4) = {4678} <> 5
- ii) 20(3) = 5{69/78} -> 5 locked for C1 -> R89C1 <> 5
b) Innies C1 = 25(6) <> 5 (I C1 = {123568}) because R89C1 would be {68}
-> blocked by Killer pair (68) of 14(4)
c) 5 locked in 20(3) @ C1 -> 20(3) <> 4
13. R123+C123 !
a) Innies N1 = 14(3): R3C3 <> 3 because
- R3C13 = [73] -> Innies R123 = 22(4) = 37{48} -> not possible because R3C8 <> 4,8
b) ! Innies N1 = 14(3) <> 3 because
- I N1 = [374] -> I R123 = 74[92/83/56]
- I R123 = [7492] -> 17(3) = 49[?]
- I R123 = [7483] -> 17(3) = [485] -> I C123 = 17(4) = 345[?]
- I R123 = [7456] -> 17(3) = [458] -> no combo for 20(3) (R3C1 = 7 but R4C3 = 8)
c) Innies N1 = 14(3) = 8{15/24} -> 8 locked for R3+N1
d) 22(3) = {679} locked for N1
e) 9(3): R1C2 <> 1 because R12C1 <> 5
f) 17(3): R4C3 <> 1 because R3C3 <> 7,9
g) Innies+Outies N23: -8 = R1C3 - R3C48; R1C3 = (1245)
-> R3C4 <> 5 because R3C8 <> 4,7,8
h) 17(3): R4C3 <> 4,5 because R3C3 <> 3,6,7,9 and R3C4 <> 4,5,8
14. C123 !
a) 3 locked in 9(3) + 14(4) for C12
b) ! 9(3) <> {135} because
- R12C1 = {13} and R3C1 = 8 -> 20(3) = 8{57} locked for C1
- R67C1 = (246) -> only {46} possible @ R14(4) -> no 2 @ C1
c) 9(3) = {234} locked for N1
d) Hidden Single: R7C1 = 1 @ C1
e) R8C2 = 3, R8C7 = 1
f) 1 locked in R13C3 for C3
15. R789
a) 3 locked in 18(4) for R9
b) 14(3) = 1{49/58/67} -> R7C7 <> 5,6
c) 16(3) <> {457} because R7C3 = (689)
d) 16(3): R6C3 <> 4 because 3 only possible there
16. C123 !
a) ! Innies+Outies C1: -5 = R17C2 - R89C1; R1C2 = (24)
-> R7C2 <> 8 because R89C1 @ 25(4) can't be {69/78/89}
b) 14(4): R6C1 <> 2
c) 2 locked in 9(3) @ C1 -> R1C2 <> 2
e) R1C2 = 4
e) ! Innies C1 = 19(3) <> {469} because R89C1 @ 25(4) can't be {69}
f) Innies C1 = 19(3) = {478} locked for C1
g) R3C1 = 5, R1C3 = 1, R3C3 = 8
h) 20(3) = {569} -> 6,9 locked for N4
i) 17(3) = 8[63/72] -> R3C4 <> 3,9; R4C3 <> 7
j) Innies = 17(4) = 18[26/35] -> R8C3 <> 2
k) Hidden Single: R7C2 @ N7 = 2 -> R6C1 = 8, R5C3 = 4 @ N4
17. C123
a) 12(3) = {147} -> {17} locked for C2+N4
b) 16(3) = {259} -> R6C2 = 5, R6C3 = 2, R7C3 = 9
c) 25(4) = {4678} -> R9C2 = 8, R9C3 = 6
d) R8C3 = 5 -> R3C8 = 3 (Outies N5689 = 8(1+1))
e) 17(3) = {368} -> R3C4 = 6, R4C3 = 3
f) 16(4) = {1258} -> R8C4 = 8, 2 locked for R9
18. R789
a) 27(4) = {5679} -> 5 locked for R9, 6 locked for R8+N8
b) 18(4) = {2349} locked for N9, R9C9 = 3
c) 14(3) @ N8 = {347}
d) 5,9 locked in R789C6 for C6
e) Innies N9 = 13(2): R7C9 <> 5,7
f) 7 locked in R79C7 for C7
19. C456
a) 11(3): R4C6 <> 7,8 because R45C7 >= 5
b) 8 locked in R45C5 for C5
c) 13(3) @ R1 = 1{39/57}
d) Killer pair (79) locked in 13(3) @ R1 + 15(3) for N2
e) 19(4) must have 1 xor 2 and R2C8 = (12) -> R1C67+R2C7 <> 2
f) 13(3) @ R2C6 must have 3,8 and it's only possible @ R2C6 -> R2C6 = (38)
g) 13(3) @ R2C6 = 1{39/48} -> R3C6 = 1
h) 3 locked in R12C6 for C6+N2
i) 13(3) @ R1 = {157}, {57} locked for R1+N2
j) 13(3) @ N5 = 2{38/47} -> R5C6 = 2
k) 9 locked in 15(3) = {159}
20. N58
a) 11(3) = 2{36/45} -> R4C7 = 2, R5C7 = (35)
b) 17(3) = {467} because (39) only possible @ R6C7
c) Naked triple (467) locked in R467C6 for C6
d) 27(4) = {5679} -> R8C6 = 9, R9C6 = 5, R9C7 = 7, R8C5 = 6
e) 14(3): R6C4 <> 3 because 3{47} blocked by R7C6 = (47)
21. Rest is singles.
Rating: Hard 2.5. I had to use some hypotheticals and massive combo analysis but those hypotheticals were of medium length.