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mhparker
Grandmaster

Joined: 20 Jan 2007
Posts: 345
Location: Germany

 Posted: Sat Mar 08, 2008 10:11 pm    Post subject: (Not the) Assassin 93 Hi folks, Fun as it is to speculate on Ruud's whereabouts and to envisage him pottering about in a gardening center near Boskoop , there's no substitute for new material to fill in the gap... Unofficial Assassin 93 (UA93) (Est. rating: 1.25) 3x3::k:2560:4353:3330:6659:6659:1797:1797:4615:4615:2560:4353:3330:3330:6659:6659:1797:6928:4615:6418:4353:6418:3605:1302:1302:6928:6928:4378:6418:6418:6418:3605:5407:5407:6928:4378:4378:5412:3109:3109:3605:5407:5161:1066:1066:4378:5412:5412:5423:5407:5407:5161:7987:7987:7987:5412:5423:5423:1337:1337:5161:7987:3901:7987:3647:5423:4929:6210:6210:3140:3140:3901:1863:3647:3647:4929:4929:6210:6210:3140:3901:1863: Happy solving!_________________Cheers, Mike
Caida
Hooked

Joined: 03 Nov 2007
Posts: 38

 Posted: Sun Mar 09, 2008 4:02 am    Post subject: Below is my walkthrough for UA93. I did some heavy combo crunching in order to break this puzzle - I'm sure there must be a more elegant solution - but I haven't found it yet. I'm definitely looking forward to seeing other walkthroughs. Thanks for this puzzle Mike! I was glad to have it as I have been struggling with Maverick #4 (and may soon have to just take a peek at the posted walkthroughs). Cheers, Caida Edited to correct a small typo - thanks Afmob! Edited to correct some more typos - thanks Andrew! UA93 Walkthrough: Preliminaries: a. 10(2)n1 = {19/28/37/46} (no 5) b. 7(3)n23 = {124} (no 3,5..9) b1. -> r1c89 no 1,2,4 (CPE) c. 5(2)n2 and n8 = {14/23} (no 5..9) d. 4(2)n6 = {13} -> locked for n6 and r5 e. 12(2)n4 = {48/57} (no 2,6,9) (1,3 already eliminated by prelim d) f. 7(2)n9 = {16/25/34} (no 7..9) g. 19(3)n78 = {289/379/469/478/568} (no 1) h. 26(4)n2 = {2789/3689/4589/4679/5678} (no 1) i. 20(3)n58 = {389/479/569/578} (no 1,2) j. 27(4)n36 = {3789/4689/5679} (no 1,2) 1. Outies c123: r29c4 = 17(2) = {89} (no 1..7) 1a. -> 8,9 locked for c4 1b. -> 13(3)n12 = {14/23}[8]/{13}[9] 1c. -> r12c3 no 5..9 2. 2 locked in n2 in 5(2) and r1c6 2a. -> no 2 elsewhere in n2 3. 26(4)n2 = {4679/5678} no 3 Note: other combos blocked by r2c4 3a. -> 6,7 locked for n2 in 26(4)n2 3b. -> 3 in n2 locked in r3 -> no 3 elsewhere in r3 4. 24(4)n8 = {2679/3579/3678/4569/4578} Note: other combos blocked by r9c4 4a. -> killer pair {89} locked in n8 in 24(4)n8 and r9c4 -> no 8,9 elsewhere in n8 5. Outies c789: r18c6 = 3(2) = {12} (no 3..9) 5a. -> 1,2 locked for c6 5b. -> r3c5 no 3,4 5c. -> pair {12} locked in n2 in r1c6 and r3c5 -> no 1,2 elsewhere in n2 5d. -> 4 in 7(3)n23 locked in r12c7 -> no 4 elsewhere in c7 and n3 6. 14(3)n25 = [347/374/356/365/437/527/572/536] (no 1) 7. Outies n47: r3c13+r9c4 = 22(2+1) = {59/68}[8]/{49/58/67}[9] 7a. -> r3c13 no 1,2 8. Outies n36: r1c6+r7c79 = 14(1+2) = [1]{49/58/67}/[2]{39/48/57} 8a. -> r7c79 no 1,2 9. Innies n8: r78c6+r9c4 = 16(3) = [718/619/628/529] 9a. -> r7c6 no 3,4 9b. -> r6c6 no 3 10. Innie and Outie r12: r3c2 – r2c8 = 1 10a. -> r3c1 no 1,2,5 10b. -> r2c8 no 9 11. Innie and Outie r89: r7c8 – r8c2 = 1 11a. -> r7c8 no 1 11b. -> r8c2 no 9 12. Outies and Innie n3: r1c6+r4c7 – r3c9 = 7 12a. -> min r3c9 = 1 -> min r1c6+r4c7 = 8 (r4c7 no 5) 12b. -> max r1c6+r4c7 = 11 -> max r3c9 = 4 (r3c9 no 5..9) 12c. -> max r3c9 = 2 -> max r1c6+r4c7 = 9 (r4c7 no 9) 12d. -> triple {124} locked in n3 in r12c7+r3c9 -> no 1,2 elsewhere in n3 12e. 9 in 27(4)n36 locked in r3c78 -> no 9 elsewhere in n3 and r3 12f. 18(3)n3 = {378/567} -> 7 locked for n3 12g. r2c8 and r3c2 no 8 (step 10) 12h. 27(4)n36 = {3789/5679} -> r4c7 = 7 12i. 7 in r3 locked in n1 -> no 7 elsewhere in n1 12j. -> r12c1 no 3 13. pair {12} in n8 locked in 5(2)n8 and r8c6 -> no 1,2 elsewhere in n8 14. Outies n6: r3c9+r7c79 = 14(1+2) 14a. -> r7c9 no 6 (no combo possible) 15. 17(3)n1 = {19}[7]/{58}[4]/{467} (no 3) Note: combo {29}[6] blocked by 10(2)n1 and combo {38}[6] blocked by 13(3)n12 (10(2)n1 would be {19} and r12c3 would be {24} -> no combo for 13(3)n12 possible) and combo {28}[7} blocked by 13(3)n12 (10(2)n1 = {19} (only place for 9) and r12c3 would be {34} -> no combo possible for 13(3)n12) 15a. -> 3 in n1 locked in r12c3 -> no 3 elsewhere in c3 15b. -> r12c3 no 4 15c. if 17(3)n1 = {179} then 10(2) = {46}; (combo {28} blocked by 13(3)n12) and if 17(2)n1 = {458/467} then 10(2)n1 = {19} (need to use the 9) 15d. -> 4 in n1 is locked in 17(3) or 10(2) -> no 4 elsewhere in n1 15e. 10(2) = {19/46} (no 2,8) 15f. -> r3c13 = {58/67} = 13(2) 15g. -> r9c4 = 9(step 7) 15h. -> r2c4 = 8 15i. -> r12c3 = {23} -> locked for c3 and n1 16. Innies n2: r1c6+r3c4 = 6(2) = [15/24] (no 3) 16a. single: r3c6 = 3 16b. -> r3c5 = 2 I got lazy - but it is all combos and cage sums to the end now Last edited by Caida on Tue Mar 11, 2008 3:39 am; edited 2 times in total
Afmob
Expert

Joined: 22 Sep 2007
Posts: 103
Location: MV, Germany

 Posted: Sun Mar 09, 2008 11:10 am    Post subject: Thanks Mike for providing a relaxing Killer. After all those 1.25 and 1.5+ Killers it was really fun to tackle an "Assassin" without spending all your brain power on it . And it's also good to see that other members post their wts as well. Edit: Fixed some typos and optimized endgame. Thanks Andrew! His hint helped me to make this my shortest wt so far (2nd best: A79). UA93 Walkthrough: 1. C789 a) Outies = 3(2) = {12} locked for C6 b) 4(2) = {13} locked for R5+N6 c) 7(3) = {124} locked between R1+N3 -> R1C89 <> 1,2,4; 4 locked for C7+N3 2. C123 a) Outies = 17(2) = {89} locked for C4 b) 12(2) <> 9 c) 13(3): R12C3 <> 5,6,7,8,9 because R2C4 = (89) 3. C456 a) 26(4) = 67{49/58} <> 2,3 because R2C4 = (89) blocks 89{27/36/45} -> 6,7 locked for N2 b) 5(2): R3C5 <> 3,4 c) Naked pair (12) locked in R1C6+R3C5 for N2 d) 3 locked in R3C456 for R3 e) Outies N5 = 10(1+1) = [37/46/55] 4. N3 a) Innies+Outies: 7 = R1C6+R4C7 - R3C9 -> R3C9 = (12) because R1C6+R4C7 <= 11 b) Naked triple (124) locked in R12C7 + R3C9 c) Innies+Outies: 7 = R1C6+R4C7 - R3C9 -> R4C7 <> 5,9 because R1C6 and R3C9 = (12) d) 27(4) = 79{38/56} -> 9 locked e) 18(3) = 7{38/56} -> 7 locked f) 27(4) = 79{38/56} -> R4C7 = 7 5. R123 a) 7 locked in R3C123 for N1 b) 10(2) <> 3 c) Naked pair (12) locked in R3C59 for R3 d) Innies+Outies R12: 1 = R3C2 - R2C8 -> R3C2 <> 5,8; R2C8 <> 9 e) 27(4) = 79{38/56} -> 9 locked for R3 f) Innies+Outies R12: 1 = R3C2 - R2C8 -> R2C8 <> 8 g) Outies R12 = 21(3): R3C2 <> 6 because 7 only possible there h) 17(3) <> 3 because R3C2 = (47) i) 3 locked in 13(3) = 3{19/28} for C3 j) Innies+Outies R12: 1 = R3C2 - R2C8 -> R2C8 <> 5 k) 27(4) must have 3 xor 6 and R2C8 = (36) -> R3C78 <> 6 6. N12 a) 6 locked in R3C13 for N1 + 25(5) b) 10(2) <> 4 c) 17(3) must have 4 xor 7 and R3C2 = (47) -> R12C2 <> 4 d) 4 locked in R3C123 for R3 e) 5(2) = [23] -> R3C5 = 2, R3C6 = 3 f) R3C4 = 5 -> 14(3) = 5{27/36} g) 26(4) = {4679} locked for N2 h) 13(3) = {238} -> R2C4 = 8; 2 locked for C3+N1 i) 7(3) = {124} -> R1C6 = 1; 2 locked for C7 j) 10(2) = {19} -> R1C1 = 9, R2C1 = 1 7. R789 a) 19(3) = {469} -> R9C4 = 9, {46} locked for C3+N7 b) 12(3) = {129} -> R8C6 = 2, R8C7 = 9, R9C7 = 1 c) 14(3) = {257} locked for N7, 2 locked for R9 d) 5(2) = {14} locked for R7+N8 8. N145 a) 17(3) = {458} -> R1C2 = 8, R2C2 = 5, R3C2 = 4 b) 12(2) = {57} -> R5C2 = 7, R5C3 = 5 c) 14(3) = {356} -> R4C4 = 3, R5C4 = 6 d) 25(5) = {12679} -> R3C1 = 6, R3C3 = 7, R4C1 = 2, {19} locked for R4+N4 9. Rest is singles. Rating: 1.0. I didn't mark any key moves but I think using Innie-Outie-Difference you can avoid combo crunching and solve it without any problems.Last edited by Afmob on Mon Mar 10, 2008 10:30 am; edited 1 time in total
Andrew
Grandmaster

Joined: 11 Aug 2006
Posts: 300
Location: Lethbridge, Alberta

 Posted: Mon Mar 10, 2008 6:53 am    Post subject: Thanks for a fun puzzle Mike. The solution really flowed well with my only real work being to put steps in the right order to simplify my solving path. Caida, Afmob and I also solved it by similar routes so there appears to be a fairly well defined although not narrow or difficult solving path. Having said that I think there were enough differences for me to also post my walkthrough. I agree with Afmob's rating of 1.0. Here is my walkthrough, which is my shortest one for a long time. Prelims a) R1C12 = {19/28/37/46}, no 5 b) R3C56 = {14/23} c) R5C23 = {39/48/57}, no 1,2,6 d) R5C78 = {13}, locked for R5 and N6, clean-up: no 9 in R5C23 e) R7C45 = {14/23} f) R89C9 = {16/25/34}, no 7,8,9 g) 7(3) cage at R1C6 = {124}, CPE no 1,2,4 in R1C89 h) R567C6 = {389/479/569/578}, no 1,2 i) 19(3) cage at R8C3 = {289/379/469/478/568}, no 1 j) 26(4) cage in N2 = {2789/3689/4589/4679/5678}, no 1 k) 27(4) cage at R2C8 = {3789/4689/5679}, no 1,2 1. 45 rule on R12 1 outie R3C2 = 1 innie R2C8 + 1, no 1,2,3 in R3C2, no 9 in R2C8 2. 45 rule on R89 1 outie R7C8 = 1 innie R8C2 + 1, no 1 in R7C8, no 9 in R8C2 3. 45 rule on N3 2 outies R1C6 + R4C7 = 1 innie R3C9 + 7, max R1C6 + R4C7 = 13 -> max R3C9 = 6 4. 45 rule on C123 2 outies R29C4 = 17 = {89}, locked for C4 4a. 13(3) cage at R1C3 = {139/148/238} (only combinations with 8 or 9) -> R12C3 = {1234} 5. 45 rule on C789 2 outies R18C6 = 3 = {12}, locked for C6, clean-up: no 3,4 in R3C5 5a. Max R1C6 + R4C7 = 11 -> max R3C9 = 4 (step 3) 5b. Min R1C6 + R4C7 = 8 (step 3) -> no 4,5 in R4C7 6. 4 of 7(3) cage locked in R12C7, locked for C7 and N3, clean-up: no 5 in R3C2 (step 1) 7. Naked pair {12} in R1C6 and R3C5, locked for N2 7a. Killer pair 1,2 in R7C45 and R8C6, locked for N8 7. 26(4) cage in N2 = {4679/5678} (cannot be {3689/4589} which clash with R2C4), no 3, 6,7 locked for N2 7a. 3 in N2 locked in R3C46, locked for R3 8. Naked triple {124} in R12C7 + R3C9, locked for N3 8a. Naked pair {12} in R3C59, locked for R3 9. Max R3C9 = 2 -> max R1C6 + R4C7 = 9 (step 3), no 9 in R4C7 10. 27(4) cage at R2C8 = {3789/5679}, 9 locked in R3C78, locked for R3 and N3, clean-up: no 8 in R2C8 (step 1) 11. 18(3) cage in N3 = {378/567}, 7 locked for N3, clean-up: no 8 in R3C2 (step 1) 12. 27(4) cage at R2C8 = {3789/5679} -> R4C7 = 7 13. R345C4 = {257/347/356} (cannot be {167} because R3C4 only contains 3,4,5), no 1 13a. 7 of {257/347} must be in R5C4 -> no 2,4 in R5C4 14. 45 rule on N1 2 innies R3C13 = 1 outie R2C4 + 5, R2C4 = {89} -> R3C13 = 13,14 = {58/67/68}, no 4 15. 7 in R3 locked in R3C123, locked for N1, clean-up: no 3 in R12C1 16. R123C2 = {179/458/467} (cannot be {269} which clashes with R12C1, cannot be {278/368} which clash with R3C13, cannot be {359} because no 3,5,9 in R3C2), no 2,3 16a. 7 of {467} must be in R3C2 -> no 6 in R3C2, clean-up: no 5 in R2C8 (step 1) 17. 3 in N1 locked in R12C3, locked for C3 17a. 13(3) cage at R1C3 (step 4a) = {139/238}, no 4 18. 27(4) cage at R2C8 = {3789/5679} 18a. 6 of {5679} -> no 6 in R3C78 19. 6 in R3 locked in R3C13, locked for N1 and 25(5) cage, clean-up: no 4 in R12C1 20. 4 in N1 locked in R123C2, locked for C2, clean-up: no 8 in R5C3 20a. R123C2 (step 16) = {458} (only remaining combination) -> R3C2 = 4, R3C56 = [23], R3C4 = 5, R3C9 = 1, R18C6 = [12], clean-up: no 9 in R2C1, no 3 in R7C45, no 6 in R89C9, no 5 in R9C9 20b. 2 in N3 locked in R12C7, locked for C7 20c. Naked pair {58} in R12C2, locked for C2 and N1 -> R5C23 = [75], R5C4 = 6, R4C4 = 3 (step 13), clean-up: no 2 in R12C1 20d. R12C1 = [91] 21. Naked pair {47} in R18C4, locked for C4 -> R7C45 = [14], R6C4 = 2, R18C4 = [47], R12C7 = [24], R12C3 = [32], R2C4 = 8 (step 17a), R9C4 = 9, R12C2 = [85] 21a. 45 rule on N8 1 remaining innie R7C6 = 5 22. 27(4) cage at R2C8 (step 18) = {3789} (only remaining combination) -> R2C8 = 3, R5C78 = [31] 23. R8C6 = 2 -> R12C7 = 10 = [91], R3C78 = [89], R67C7 = [56] 23a. 45 rule on N9 1 remaining innie R7C9 = 7, R12C9 = [56], R1C8 = 7, R1C5 = 6, clean-up: no 2 in R9C9 24. Naked pair {38} in R89C5, locked for C5 and N8 -> R9C6 = 6, R5C5 = 9, R2C56 = [79], R46C5 = [51] 25. R9C4 = 9 -> R89C3 = 10 = [64] and the rest is naked singles and a cage sum 9 8 3 4 6 1 2 7 5 1 5 2 8 7 9 4 3 6 6 4 7 5 2 3 8 9 1 2 9 1 3 5 4 7 6 8 4 7 5 6 9 8 3 1 2 3 6 8 2 1 7 5 4 9 8 3 9 1 4 5 6 2 7 5 1 6 7 3 2 9 8 4 7 2 4 9 8 6 1 5 3Last edited by Andrew on Sun Mar 16, 2008 12:01 am; edited 1 time in total
gary w

Joined: 07 Sep 2007
Posts: 84
Location: south wales

 Posted: Mon Mar 10, 2008 4:00 pm    Post subject: Sorry to be a bit heretical but I've actually enjoyed NOT doing an assassin for a couple of weeks.Now I feel a bit fresher and looking forward to future challenges whereas all those 1.25+ brutes were beginning to wear me down!! Regards Gary P.S. Aside from Ruud,what's happened to Cathy and Para??
mhparker
Grandmaster

Joined: 20 Jan 2007
Posts: 345
Location: Germany

Posted: Mon Mar 10, 2008 11:01 pm    Post subject:

 gary w wrote: Now I feel a bit fresher...

...and posting during daylight hours, I see!

 gary w wrote: P.S. Aside from Ruud,what's happened to Cathy and Para??

Don't know about Cathy (doesn't the poor girl get given lunch breaks any more?! ), but I recently saw that Para is driving for a go-cart racing team this season Makes a bit of a change from Sudoku! Maybe he'll be back sometime and tell us how it went.
_________________
Cheers,
Mike
Glyn
Major Major Major

Joined: 16 Jan 2007
Posts: 92
Location: London

 Posted: Tue Mar 11, 2008 10:25 am    Post subject: Cathy had mentioned both on here and over at Djape that she would have less time to participate for a while. Same story here at present. Keep up the good work everyone._________________I have 81 brain cells left, I think.
gary w

Joined: 07 Sep 2007
Posts: 84
Location: south wales

 Posted: Tue Mar 11, 2008 11:09 pm    Post subject: For a change I did this week's "mind bending" killer on killersudokuonline,number 114.Quite good fun..I'ld rate it as harder than the Times deadly ones but easier than any assassins,so about a 0.75. the outies for nonet 6 plus possible combos for r37c8 together with the 45 cage -> r7c78={17} -> r9c34=27 enables a pretty quick solution Not quite daytime hours Mike but,yes,another early posting from me. Regards Gary
mhparker
Grandmaster

Joined: 20 Jan 2007
Posts: 345
Location: Germany

Posted: Wed Mar 12, 2008 9:26 am    Post subject:

 gary w wrote: Sorry to be a bit heretical but I've actually enjoyed NOT doing an assassin for a couple of weeks.

 gary w wrote: For a change I did this week's "mind bending" killer on killersudokuonline,number 114.

Gary, please don't feel obliged to take a break just because Ruud is! As you can see, there have been plenty of puzzles from other forum members in recent times, and I can assure you that the supply is not going to dry up anytime soon!

Starting with the UA93, I'm also releasing some puzzles of traditional V1 standard, which should be more fun to solve for the majority of people (both registered and unregistered) visiting this forum.

BTW, even before Ruud's recent break, I was beginning to get concerned that the Assassins were generally becoming too difficult (probably as a result of unreleased enhancements to SumoCue). In particular, we weren't getting any 1.0-rated puzzles any more. Not only did this probably restrict their appeal to a narrower audience, but it also gave the rest of us less chance of creating a good V2. Indeed, I was even starting to consider producing "Lite" variants instead of V2s at times!
_________________
Cheers,
Mike
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