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Sudtyro
Hooked

Joined: 16 Jan 2007
Posts: 49

Posted: Thu Mar 22, 2007 9:35 pm    Post subject: 1/23/07 Nightmare...talk about being behind!

Running through the basics yields the following grid:
 Code: 357  1   8  | 57  9   67   | 4      2    3567 257  9   6  | 4   3   12   | 157    17   8 2357 57  4  | 18  567 128  | 13567  167  9 ------------+--------------+----------------- 9    568 2  | 3   157  4   | 15678  1678 567 1    56  3  | 578 2    78  | 567    9    4  45   458 7  | 6   15   9   | 1258   3    25 ------------+--------------+----------------- 4678 3   19 | 2   467  167 | 6789   5    67 4678 2   5  | 79  467  3   | 6789   4678 1  467  47  19 | 19  8    5   | 23     467  23

Some 3D coloring of the 3s cluster, plus the locked 7s and 4s in c2, leads to AIC1:
(3)r1c1 = (3)r1c9  (3=2)r9c9  (2=5)r6c9  (5=4)r6c1  (4)r6c2 = (4-7)r9c2 = (7)r3c2 => r1c1 <> 7.
AIC1 yields a second elimination by replacing the first node with (3)r3c7 to form AIC2:
(3)r3c7 = (3)r1c9  (3=2)r9c9  (2=5)r6c9  (5=4)r6c1  (4)r6c2 = (4-7)r9c2 = (7)r3c2 => r3c7 <> 7.
And the new (35)r1c1 bi-value then allows for AIC3:
(5)r3c5 = (5)r1c4  (5=3)r1c1  (3)r1c9 = (3)r3c7 => r3c7 <> 5.

QUESTION 1: Is it possible to combine the first two AIC's using notation something like:
(3)r1c1|r3c7 = (3)r1c9  (3=2)r9c9  (2=5)r6c9  (5=4)r6c1  (4)r6c2 = (4-7)r9c2 = (7)r3c2 => r1c1|r3c7 <> 7?
QUESTION 2: Would the notation, (3)r1c9|r3c1, be OK to designate alternate paths available at the fourth node in AIC3?
QUESTION 3: Any suggestions for alternative techniques to get these same three eliminations (e.g., ALSs, Wings, etc.)?

The resulting grid now appears as:
 Code: 35   1   8  | 57  9    67  | 4      2    3567 257  9   6  | 4   3    12  | 157    17   8 2357 57  4  | 18  567  128 | 136    167  9 ------------+--------------+----------------- 9    568 2  | 3   157  4   | 15678  1678 567 1    56  3  | 578 2    78  | 567    9    4  45   458 7  | 6   15   9   | 1258   3    25 ------------+--------------+----------------- 4678 3   19 | 2   467  167 | 6789   5    67 4678 2   5  | 79  467  3   | 6789   4678 1  467  47  19 | 19  8    5   | 23     467  23

And I hit a brick wall at this point.
QUESTION 4: Can anyone provide a hint or two to manually advance from here?
Ruud
Site Owner

Joined: 30 Dec 2005
Posts: 601

 Posted: Thu Mar 22, 2007 10:38 pm    Post subject: Here is a (somewhat) cryptic hint: Too bad George Clooney left ER in season 5. Ruud_________________If the human brain were so simple that we could understand it, we would be so simple that we couldn't. - Emerson M Pugh
Sudtyro
Hooked

Joined: 16 Jan 2007
Posts: 49

 Posted: Fri Mar 23, 2007 11:54 am    Post subject: George Clooney QUESTION 5: Is it possible that the site owner is having just a little too much fun with all of this? Edit: And BTW...thanks! If it'd been a Turbot SNAKE it would've bit me!
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