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June 2, 2007 Nightmare - A BUG-Lite AIC

 
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Myth Jellies
Hooked
Hooked


Joined: 04 Apr 2006
Posts: 42

PostPosted: Sat Jun 02, 2007 4:53 pm    Post subject: June 2, 2007 Nightmare - A BUG-Lite AIC Reply with quote

Code:
 *-----------*
 |4..|.3.|..1|
 |..5|...|7..|
 |71.|.9.|.85|
 |---+---+---|
 |...|...|...|
 |5..|8.6|..7|
 |19.|...|.52|
 |---+---+---|
 |...|.8.|...|
 |82.|3.1|.74|
 |.7.|...|.3.|
 *-----------*
 *--------------------------------------------------------------------*
 | 4      68     2689   |*57     3     *57     | 269    26     1      |
 | 269    36     5      | 126    14     8      | 7      246    369    |
 | 7      1      236    | 26     9      24     | 2346   8      5      |
 |----------------------+----------------------+----------------------|
 | 26     3468   7      |*59+12 #125   *59     | 13468  146    368    |
 | 5      34     23     | 8      12     6      | 134    9      7      |
 | 1      9      68     | 4      7      3      | 68     5      2      |
 |----------------------+----------------------+----------------------|
 | 3      5      14     |*79+2   8     *79+24  | 126    126   #69     |
 | 8      2      69     | 3      56     1      | 59     7      4      |
 | 69     7      14     | 259    2456   2459   | 1258   3      89     |
 *--------------------------------------------------------------------*

I used a little BUG-Lite AIC to solve this one. Note that the only way to avoid the 57-79-95 BUG-Lite deadly pattern in r147c46 is for either the 5 in row 4 to escape to r4c5, or for the 9 in row 7 to escape to r7c9. Extending that by a bivalue cell, we get...

(5)r4c5 = (59-57-79 BUG-Lite)r147c46 = (9)r7c9 - (9=5)r8c7 => r8c5 <> 5

...and the puzzle is cracked.
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