SudoCue Users

Number 4 is LOCKED in R1C1 and R1C3. If there is naked pair 4-7 then we have R1C5=1, R3C4=7, R4C7=7 and R6C3=4. So we ken eliminate number 7 from R1C1 or R1C1=4.

There is few more this kind of elimination...

Hi Steve. My point is: If r8c1 = 8 then r9c1=6 so r9c1 ≠ 5. Generally: There is two cells (in the box/ column/ row) with locked candidate A: cell1 = ABCD cell2 = ABCFG If cell1 = B(or C or D) then cell2 = A .... Bat my point is: cell2 is not equal to B(or C or F or G) And now about solving...

Let's use this code from another topic. Code: .------------------.------------------.------------------. | 7 6 1 | 8 3 2 | 4 9 5 | | 4 9 8 | 1 6 5 | 2 37 37 | | 3 5 2 | 4 9 7 | 6 1 8 | :------------------+------------------+------------------: | 9 38 67 | 36 4 1 |*378 5 2 | |*58 4 35 | 2 7 9 | 1 *36...

Hi Ruud! I'm sorry, it's just oversight, it is R9C7=5. And about rule: for me is easier to consider 2 or 3 cells in line (in the same box), at the same time, and see what is result. I need help because I'm not sure is this right way. Novajlija = Fresh Blood

Let's use this code from another topic. .-----------------------.-----------------------.-----------------------. |7 6 1 |8 3 2 |4 9 5 | |4 9 8 |1 6 5 |2 37 37 | |3 5 2 |4 9 7 |6 1 8 | :-----------------------+-----------------------+-----------------------: |9 38 67 |63 4 1 |378 5 2 | |58 4 35 |2 7...