5/20/07 Nightmare...7's grid

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Sudtyro
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5/20/07 Nightmare...7's grid

Post by Sudtyro »

The following 7's grid was derived from the full puzzle after running through the basics, and after two short Turbot chains and one XY-Wing.

Code: Select all

. 7 . | . . 7 | . . .
. . . | . . . | . . .
. 7 . | 7 . . | . . .
------+-------+------
. . . | 7 . . | . . 7
. . . | 7 . 7 | 7 . .
. . . | . . . | . . .
------+-------+------
7 . . | . . . | . . 7
7 . . | . . . | 7 . 7
. . . | . . . | . . .
I'm working with this grid as part of a new ALS search strategy to be posted soon. But, now I'm totally Para-noid! :)
Please tell me....is there a fish in here?
Ruud
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Post by Ruud »

Sudtyro wrote:is there a fish in here?
:no:
“If the human brain were so simple that we could understand it, we would be so simple that we couldn't.” - Emerson M Pugh
Myth Jellies
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Post by Myth Jellies »

There is a trick.

For there to be a stand-alone fish, you have to be able to have candidates seeing each other in a loop through the unsolved boxes. With this setup, the only cyclic path through any of the unsolved boxes would be b1-b2-b5-b6-b9-b7-b1.... Since the candidates in b1 and b7 cannot directly see each other, there is no cyclic box path so there won't be a useful stand-alone fish or coloring reduction (outside of possibly a line-box or box-box locked candidates deduction).
Sudtyro
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Post by Sudtyro »

Myth Jellies wrote:There is a trick.
Thanks, MJ...that's really helpful!
Sudtyro
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Post by Sudtyro »

MJ,

One quick follow-up question on your "trick"...
Does “stand-alone” mean naked only, or can a successful cyclic path also indicate a possible hidden fish?
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Post by Myth Jellies »

I am not sure what a hidden fish is. Unlike locked sets where a naked set is coupled with a hidden set, a fish group is always coupled with just another fish group.

By stand-alone, I meant a fish deduction that could not be represented more simply, like with a hidden single or locked candidates deduction.

To show what I mean, in your example, pretend that the 7 in r4c4 does not exist. Then you would have an r135/c246 swordfish acting to eliminate r5c7, but you would also have the simpler locked candidates in box 5 row 5 making the same deduction.
Sudtyro
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Post by Sudtyro »

Got it...thanks!
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