Ron@ldK wrote:Step 1: 45 test eliminates in 3 outies of rows 1,2
It leaves 9 for the 3 outies, that implies three combinations for
the 9, 1,2,6 / 1,3,5 and 2,3,4
The 3 outies add up to (16+15+17+21+17+15+11-90) = 22. Since it cannot go below {589}, all candidates 1,2,3 & 4 are scrapped.
Step 2: Unplaceable candidate in cage 11(3) in nonet 3
In my opinion only the 9 is not placeable.
This is the result of your incorrect calculation in step 1. Because the outie must be 5 or higher, the other 2 digits must add up to 6 or less, but {15} is impossible because it would result in a repeating 5.
Step 3: 45 test eliminates in 3 outies of rows 1,2
I don't see the difference with step 1
Read carefully: it reads "columns" and not "rows"
The outies add up to 9 (maybe you tested the columns in step 1?). The highest possible number is 6 in {126}
Step 4: 45 test eliminates in 3 outies of rows 8,9
It leaves 9 for the 3 outies, that implies three combinations for
the 9, 1,2,6 / 1,3,5 and 2,3,4
Again: Columns, not rows. The surplus is 7 for the 3 outies. {124} is the only configuration for that.
Step 5: Unplaceable candidates in cage 16(3) in nonet 9
I don't see any candidates
I like this one. Hard to find indeed. The outie cell has {124} after the preious step. If you press X (show configurations) you will see that there are no configurations that contain 2 of these digits, which means that the other 2 cells cannot place them.
Step 6: Naked subset of size 3 found in column 7
What is the meaning of this
Step 4 caused 3 cells in column 7 with candidates {124}. These 3 cells will be the ONLY spots in column 7 that can contain 1, 2 or 4. All other cells in column 7 can be cleared of these digits. For more details, read my online solving guide.
Step 7: Unplaceable candidates in cage 9(3) in nonet 2,3,6
The combination for 9 can be 1,2,6 / 1,3,5 or 2,3,4 , so 7,8,9 are
not placeable.
This is because you did not take the previous step into account. The 2 cells in column 7 no longer have digits 1,2 & 4 as candidate. As a result, the combination {126} no is longer valid. This eliminates 6. Now the 2 cells in column 7 only allow {3,5}, so the other cell can only be 1.
Step 8: Digit 1 is placed in r3c6
Perfectly logical.
Difficult killers like these must be handled with care. Read the hints carefully, do not confuse rows & columns, and check your calculations.
Ruud